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Chemistry
The dissociation constant of a weak monoprotic acid, which is 0.01 % ionised in 1.00M solution, is
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Q. The dissociation constant of a weak monoprotic acid, which is $0.01\%$ ionised in $1.00M$ solution, is
NTA Abhyas
NTA Abhyas 2022
A
$1\times 10^{- 8}$
0%
B
$1\times 10^{- 4}$
0%
C
$1\times 10^{- 6}$
100%
D
$10^{- 5}$
0%
Solution:
$K =\frac{\alpha^2 C }{1-\alpha} ; 1-\alpha \approx 1$
$\therefore K =\alpha^2 C =\left[\frac{0.01}{100}\right]^2 \times 1$
$=1 \times 10^{-8}$