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Q.
The dissociation constant of a substituted benzoic acid is $1.0\times 10^{- 4}$ at $25^{o}C$ . The pH of 0.01 M solution of its sodium salt is
NTA AbhyasNTA Abhyas 2022
Solution:
For a salt of a weak acid and strong base
$pH=7+\frac{1}{2}pKa+\frac{1}{2}logC$
$=7+\frac{1}{2}\left(-\log 1 \times 10^{-4}\right)+\frac{1}{2} \log (0.01)$
$=8.$