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  4. The displacement vs time of a particle executing SHM is shown in figure. The initial phase φ is

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Q. The displacement vs time of a particle executing SHM is shown in figure. The initial phase $\phi$ isPhysics Question Image

Oscillations

Solution:

For $x=(- A )$,
we have $-A=A \sin \left(\omega \times 0+\phi_0\right)$
or $\phi_0=-\frac{\pi}{2}$.
So for $x<(-A), \phi_0<(-\pi / 2)$.