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Q. The displacement time graph of a particle moving along a straight line is drawn below.
The accelerations of the particle during the regions $OP, PQ$ and $QR$ are
OP PQ QR
A - 0 +
B + 0 +
C + 0 -
D - 0 -
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AIIMSAIIMS 2008Motion in a Straight Line

Solution:

Acceleration $=\frac{d^{2}x}{dt^{2}}$
For part OP, the acceleration is positive as the velocity is increasing. Slope is increasing. For part PQ, the acceleration is zero. Horizontal straight line shows that the velocity is zero. For part QR, acceleration is negative. It is retarded motion. Velocity is decreasing as the slope decreases with time. Hence option (c) is correct.