Question

The displacement-time graph of a particle executing $ SHM $ is shown below

Which of the following statement (s) is are true?
(i) The force is zero at $ t =3 \, T/4 $
(ii) The acceleration is maximum at $ t=T $ ,
(iii) The velocity is maximum at $ t=T/4 $
(iv) The potential energy is equal to kinetic energy at $ t = T/2 $

• A. (i) and (ii)
• B. (i), (ii) and (iii)
• C. (i) and (iv)
• D. All of the above

Answer 1

Answer: (B)

(i) The force will be zero at $t=\frac{3T}{4}$ (when the particle is at mean position)

(ii) The acceleration will be maximum at extreme position (for $t = T$ )
(iii) Velocity will be maximum at mean position $\left(t=\frac{T}{4}\right)$ where as at $\frac{T}{2}PE$ will be maximum $KE$ will be zero