Thank you for reporting, we will resolve it shortly
Q.
The displacement-time graph of a moving particle with constant acceleration is shown in figure. The velocity-time graph is given by
Motion in a Straight Line
Solution:
At $t=0$, slope of the $x-t$ graph is zero; hence, velocity is zero at $t=0$. As time increases, slope increases in negative direction; hence, velocity increases in negative direction.
At point (1), slope changes suddenly from negative to positive value; hence, velocity changes suddenly from negative to positive and then velocity starts decreasing and becomes zero at (2).
Option (a) represents all these clearly.
