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  4. The displacement of a particle moving on a circular path when it makes 60° at the centre is

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Q. The displacement of a particle moving on a circular path when it makes $60^{\circ}$ at the centre is

Motion in a Plane

Solution:

In the figure, $A B$ is the required displacement of the particle.
In triangle $O A B, O A=O B$ and $\angle A O B=60^{\circ}$
image
Therefore, $\triangle A O B$ is an equilateral triangle, so
$O A=O B=r=A B $.