Question

The displacement of a particle is represented by the equation $y=\sin ^{3} \omega t .$ The motion is

• A. non-periodic
• B. periodic but not simple harmonic
• C. simple harmonic with period $2 \pi / \omega$
• D. simple harmonic with period $\pi / \omega$

Answer 1

Answer: (B)

Given, $y=\sin ^{3} \omega t=\frac{1}{4}[3 \sin \omega t-\sin 3 \omega t]$ As this motion is not represented by single harmonic function, hence it is not SHM. As this motion involves sine and cosine functions, hence it is periodic motion.