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Q. The displacement of a body is given to be proportional to the cube of time elapsed. The magnitude of the acceleration of the body, is

AIIMSAIIMS 1996

Solution:

Given that displacement of the body,
$y \,\propto\,t^{3}$
or$\,\,\,\,\,y = kt^{3}$
$\therefore \,\,\,\,\,v = \frac{dy}{dt } = 3kt^{2}$
or $\,\,\,\,a = \frac{dv}{dt} = 6\,kt \propto$ t
$\therefore \,\,\,\,\,$ The magnitude of the acceleration of the bodyincreases with time.