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Chemistry
The dipole moment of H2S is 0.95 D. If the bond angle is 97° , the S-H bond moment would be (cos 48.5 =0.662)
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Q. The dipole moment of $H_2S$ is 0.95 D. If the bond angle is $97^\circ $, the S-H bond moment would be (cos 48.5 =0.662)
KEAM
KEAM 2005
Chemical Bonding and Molecular Structure
A
0.95 D
18%
B
0.662 D
11%
C
48.5 D
7%
D
0.72 D
57%
E
7.2 D
57%
Solution:
$\mu_{obs}=\mu_{S-H}Cos97^\circ 2\mu_{S-H}cos48.5$
$0.95=2\mu_{S-H}\times0.662$
$\mu_{S-H}=\frac{0.95}{2\times0.662}=0.72D$