Question

The dimensions of viscosity coefficient are:

• A. $ M{{L}^{-1}}{{T}^{-1}} $
• B. $ ML{{T}^{-1}} $
• C. $ M{{L}^{-1}}T $
• D. $ MLT $
• E. $ ML{{T}^{-2}} $

Answer 1

Answer: (A)

From Newtons formula: $ \eta =\frac{F}{A(\Delta {{v}_{x}}/\Delta z)} $ Dimensions of $ \eta =\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}][L{{T}^{-1}}/L]}=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}][{{T}^{-1}}]} $ $ =M{{L}^{-1}}{{T}^{-1}} $