Question

The dimensions of potential difference are

• A. $ [M{{L}^{2}}{{T}^{2}}{{Q}^{-1}}] $
• B. $ [M{{L}^{2}}{{T}^{2}}{{Q}^{2}}] $
• C. $ [L{{T}^{2}}Q] $
• D. $ [{{M}^{2}}L{{T}^{2}}{{Q}^{-1}}] $

Answer 1

Answer: (A)

It is clear that potential difference between any two points is the amount of work done, when a unit charge moves from one point to other $ V=\frac{\text{Work}\,\,\text{done}}{\text{Charge}\,\,\text{moved}}=\frac{W}{Q} $ Hence, the dimensions of potential difference $ =\frac{\text{Dimension of work done}}{\text{Dimension of charge moved}} $ $ =\frac{[M{{L}^{2}}{{T}^{-2}}]}{[Q]} $ $ =[M{{L}^{2}}{{T}^{-2}}{{Q}^{-1}}] $