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Q. The dimensions of Planck's constant is same as that of

AFMCAFMC 2011

Solution:

Dimensions of Planck's constant
$h =$ Dimension of $\frac{E}{V}$
$=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ T ^{-3}\right]}=\left[ ML ^{2} T ^{-1}\right]$
Dimensions of angular momentum
$=$ Dimension of $ m v r$
$=\left[ MLT ^{-1}\right][ L ] $
$= \left[ ML ^{2} T ^{-1}\right]$