Question

The dimensions of $\left(\frac{ B ^2}{\mu_0}\right)$ will be : (if $\mu_0$ : permeability of free space and B : magnetic field)

• A. $\left[ M L ^2 T ^{-2}\right]$
• B. $\left[ M L T ^{-2}\right]$
• C. $\left[ M L ^{-1} T ^{-2}\right]$
• D. $\left[ M L ^2 T ^{-2} A ^{-1}\right]$

Answer 1

Answer: (C)

$u =\frac{ B ^2}{2 \mu_0}$
$u \rightarrow$ Energy per unit volume
${\left[\frac{ B ^2}{\mu_0}\right]=[ u ]=\frac{\left[ ML ^2 T ^{-2}\right]}{\left[ L ^3\right]}=\left[ ML ^{-1} T ^{-2}\right]}$