Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The dimensions of $\left(\frac{ B ^2}{\mu_0}\right)$ will be : (if $\mu_0$ : permeability of free space and B : magnetic field)

JEE MainJEE Main 2022Physical World, Units and Measurements

Solution:

$ u =\frac{ B ^2}{2 \mu_0} $
$ u \rightarrow $ Energy per unit volume
$ {\left[\frac{ B ^2}{\mu_0}\right]=[ u ]=\frac{\left[ ML ^2 T ^{-2}\right]}{\left[ L ^3\right]}=\left[ ML ^{-1} T ^{-2}\right]}$