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Q. The dimensions of angular momentum are same as that of

UP CPMTUP CPMT 2009

Solution:

Planck's constant
$h=\frac{\text{Energy E}}{\text{Frequency} \upsilon}$
$=\frac{\left[ML^{2}T^{-2}\right]}{\left[T\right]}$
$=\left[ML^{2}T^{-1}\right]$
Angular momentum L = Moment of inertia I\times angular velocity $\omega$
$L=\left[ML^{2}\right]\left[T^{-1}\right]=\left[ML^{2}T^{-1}\right]$