Question

The dimensional formula of Planck's constant $(h)$ is

• A. $\left[M L^{-2} T^{-3}\right]$
• B. $\left[M L^{2} T^{-1}\right]$
• C. $\left[M L T^{-2}\right]$
• D. $\left[M L^{-2} T^{-1}\right]$

Answer 1

Answer: (B)

away from the coil (Lenz's law).
Hence, acceleration of the falling magnet is less than $g$.
From Planck's law, energy of a photon of frequency $v$ is given by $E=h v$
where $h$ is Planck's constant.
$\therefore $ Dimensions of $h=\frac{\text { Dimensions of } E }{\text { Dimensions of } v }$
Dimensions of $h=\frac{\left[M L^{2} T^{-2}\right]}{\left[T^{-1}\right]}$
$\left[M L^{2} T^{-1}\right]$