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Q. The dimensional formula of permeability of free space $\mu_0$ is

AIPMTAIPMT 1991Physical World, Units and Measurements

Solution:

Permeability of free space
$\mu_{0}=\frac{2 \pi \times \text { force } \times \text { distance }}{\text { current } \times \text { current } \times \text { length }}$
Dimensional formula of $\mu_0=\frac{[MLT^{-2}][L]}{[A][A][L]}$
$ =[MLT^{-2}A^{-2}]$