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Q. The dimensional formula of magnetic permeability is

NTA AbhyasNTA Abhyas 2022

Solution:


$\frac{F}{l}=\frac{\mu _{0} I_{1} I_{2}}{2 \pi r}$
Or $\left[\mu _{0}\right]=\frac{\left[\right. F \left]\right.}{\left[\right. I_{1} I_{2} \left]\right.}=\frac{\left[\right. M L T^{- 2} \left]\right.}{\left[\right. A^{2} \left]\right.}=\left[\right.MLT^{- 2}A^{- 2}\left]\right.$ .