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Q.
The dimensional formula of magnetic induction $B$ is
NTA AbhyasNTA Abhyas 2022
Solution:
$F_{m}=Bqv$
or $\left[B\right]=\left[\frac{F_{m}}{q v}\right]=\left[\frac{F_{m}}{I t v}\right]$
$=\frac{\left[M L T^{- 2}\right]}{\left[A\right] \left[T\right] \left[\right. L T^{- 1} \left]\right.}=\left[\right.ML^{0}T^{- 2}A^{- 1}\left]\right.$