Question

The dimension of $ K $ in the equation $ W=\frac{1}{2}Kx^{2} $ is

• A. $ \left[M^{1}L^{0}T^{-2}\right] $
• B. $ \left[M^{0}L^{1}T^{-1}\right] $
• C. $ \left[M^{1}L^{1}T^{-2}\right] $
• D. $ \left[M^{1}L^{0}T^{-1}\right] $

Answer 1

Answer: (A)

$W=\frac{1}{2}kx^{2}$
Writing the dimensions on both sides
$[ML^{2}T^{-2}] =k [M^{0}L^{2}T^{0}]$
$\therefore $ Dimension of $k=[ML^{-2}]=[ML^{0}T^{-2}]$