Question

The differential rate law for the reaction,
$4NH_{3}\left(g\right)+5O_{2}\left(g\right) \rightarrow 4NO\left(g\right)+6H_{2}O\left(\right.g\left.\right)$

• A. $-\frac{\text{d} \left[\text{N} \text{H}_{3}\right]}{\text{d} \text{t}}=-\frac{\text{d} \left[\text{O}_{2}\right]}{\text{d} \text{t}}=-\frac{\text{d} \left[\text{N} \text{O}\right]}{\text{d} \text{t}}=-\frac{\text{d} \left[\right. \text{H}_{2} \text{O} \left]\right.}{\text{d} \text{t}}$
• B. $\frac{\text{d} \left[\text{N} \text{H}_{3}\right]}{\text{d} \text{t}}=\frac{\text{d} \left[\text{O}_{2}\right]}{\text{d} \text{t}}=-\frac{1}{4}\frac{\text{d} \left[\text{N} \text{O}\right]}{\text{d} \text{t}}=-\frac{1}{6}\frac{\text{d} \left[\right. \text{H}_{2} \text{O} \left]\right.}{\text{d} \text{t}}$
• C. $\frac{1}{4}\frac{\text{d} \left[\text{N} \text{H}_{3}\right]}{\text{d} \text{t}}=\frac{1}{5}\frac{\text{d} \left[\text{O}_{2}\right]}{\text{d} \text{t}}=\frac{1}{4}\frac{\text{d} \left[\text{N} \text{O}\right]}{\text{d} \text{t}}=\frac{1}{6}\frac{\text{d} \left[\right. \text{H}_{2} \text{O} \left]\right.}{\text{d} \text{t}}$
• D. $-\frac{1}{4}\frac{\text{d} \left[\text{N} \text{H}_{3}\right]}{\text{d} \text{t}}=-\frac{1}{5}\frac{\text{d} \left[\text{O}_{2}\right]}{\text{d} \text{t}}=\frac{1}{4}\frac{\text{d} \left[\text{N} \text{O}\right]}{\text{d} \text{t}}=\frac{1}{6}\frac{\text{d} \left[\right. \text{H}_{2} \text{O} \left]\right.}{\text{d} \text{t}}$

Answer 1

Answer: (D)

The differential rate law for the reaction,
$4\text{N}\left(\text{H}\right)_{3}\left(\text{g}\right)+5\left(\text{O}\right)_{2}\left(\text{g}\right) \rightarrow 4\text{N}\text{O}\left(\text{g}\right)+6\left(\text{H}\right)_{2}\text{O}\left(\right.\text{g}\left.\right)$ is
$\text{R}\text{a}\text{t}\text{e}=-\frac{1}{4}\frac{\text{d} \left[\text{N} \text{H}_{3}\right]}{\text{d} \text{t}}=-\frac{1}{5}\frac{\text{d} \left[\text{O}_{2}\right]}{\text{d} \text{t}}$
$=+\frac{1}{4}\frac{\text{d} \left[\text{N} \text{O}\right]}{\text{d} \text{t}}=+\frac{1}{6}\frac{\text{d} \left[\right. \text{H}_{2} \text{O} \left]\right.}{\text{d} \text{t}}$