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Q. The differential equation of $y = e^{bx}$ (a and b are parameter) is

Differential Equations

Solution:

$y = e^{bx}$
$\Rightarrow y_{1} = ba\,e^{bx}$
$\Rightarrow y_{2} = ab^{2}\,e^{bx}$
$\therefore y^{2}_{1} = a^{2}\,b^{2}\,e^{2bx}$
$= \left(a \,e^{bx}\right) \left(ab^{2}\, e^{bx}\right) = y\, y_{2}$
$\therefore y\,y_{2} = y^{2}_{1}$.