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Q. The difference of water molecules in gypsum and plaster of Paris is

Jharkhand CECEJharkhand CECE 2015

Solution:

Formula of gypsum $ =CaS{{O}_{4}}.2{{H}_{2}}O $
Formula of plaster of Paris $ =CaS{{O}_{4}}.\frac{1}{2}{{H}_{2}}O $
Thus, difference of water molecule
$ =2{{H}_{2}}O-\frac{1}{2}{{H}_{2}}O=1\frac{1}{2}{{H}_{2}}O $