1. Tardigrade
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  3. Chemistry
  4. The difference (in kJ ) between Δ H and Δ E on a molar basis for the combustion of n-octane at 25° C would be :

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Q. The difference (in $kJ$ ) between $\Delta H$ and $\Delta E$ on a molar basis for the combustion of $n$-octane at $25^{\circ} C$ would be :

Thermodynamics

Solution:

$\Delta H -\Delta E =-4.5 \times 8.315 \times 298 \,J$
$ =-11.15\, kJ$