Question

The difference between orbital angular momentum of an electron in a $4 \,f$ orbital and another electron in a $4\, s$ orbital is

• A. $2 \sqrt{3}$
• B. $3 \sqrt{2}$
• C. $3$
• D. $2$

Answer 1

Answer: (A)

Orbital angular momentum $=\sqrt{l(l+1)} \frac{h}{2 \pi}$
For $4 f$ orbital; $l=3$
Orbital angular momentum
$=\sqrt{3(3+1)} \frac{h}{2 \pi}=2 \sqrt{3} \frac{h}{2 \pi}$
For $4 s$ orbital; $l=0$
$ \therefore $ Orbital angular momentum $=0$
$\therefore $ Difference $=2 \sqrt{3} \frac{h}{2 \pi}$