1. Tardigrade
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  3. Chemistry
  4. The difference between heat of reaction at constant pressure ( triangle H) and at constant volume (.ΔE.) for the reaction: C(s)+(1/2)O2 (g) arrow (CO)(g) is :- (Assume R=0.002KcalK- 1mol- 1 and temperature =TK )

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Q. The difference between heat of reaction at constant pressure $\left(\triangle H\right)$ and at constant volume $\left(\right.ΔE\left.\right)$ for the reaction: $C_{\left(s\right)}+\frac{1}{2}O_{2 \left(g\right)} \rightarrow \left(CO\right)_{\left(g\right)}$ is :-
(Assume $R=0.002KcalK^{- 1}mol^{- 1}$ and temperature $=TK$ )

NTA AbhyasNTA Abhyas 2020

Solution:

$\triangle H-\triangle E=\triangle n_{g}RT$
$=\frac{1}{2}\times 0.002\times TKcal$
$=\frac{T}{2}cal$