Thank you for reporting, we will resolve it shortly
Q.
The difference between $\Delta H$ and $\Delta U (\Delta H- \Delta U)$, when the combustion of one mole of heptane (I) is carried out at a temperature $T$, is equal to:
$C _7 H _{16}(\ell)+11 O _2( g ) \longrightarrow 7 CO _2( g )+8 H _2 O (\ell)$
$\Delta ng = np - nr =7-11=-4$
$\because \Delta H=\Delta U+\Delta n_g R T$
$\therefore \Delta H-\Delta U=-4 R T$