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Q. The diameter of the lens of a telescope is $0.61 \, m$ and the wavelength of light used is $5000 \, \text{Å}$ . The resolution power of the telescope is

NTA AbhyasNTA Abhyas 2020Wave Optics

Solution:

Resolving power $\left(\frac{1}{d \theta }\right)=\frac{D}{1.22 \lambda }$
$=\frac{0.61}{1.22 \times 5000 \times 10^{- 10}}$
$=10^{6}$