1. Tardigrade
  2. Question
  3. Physics
  4. The diagram shows a small bead carrying charge q. The bead can freely move on smooth fixed ring placed on a smooth horizontal plane. Potential due to + Q at 1 is V. If bead is given a very small velocity tangential from Q Velocity of bead when it reaches at 1 (mass of bead is m ) <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/756e7bbeef3e2337475ef2c16d998d79-.png />

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The diagram shows a small bead carrying charge $q.$ The bead can freely move on smooth fixed ring placed on a smooth horizontal plane. Potential due to $+ Q$ at 1 is $V.$ If bead is given a very small velocity tangential from $Q$ Velocity of bead when it reaches at $1 $ (mass of bead is $m$ )
image

Electric Charges and Fields

Solution:

As between $(a)$ and $(b)$
$\Delta v =3 V$
$\Rightarrow $ work $=\Delta KE$
$\Rightarrow 3 qV =\frac{1}{2} mv ^{2}$
$\Rightarrow v=\sqrt{\frac{6 q V}{m}}$
image