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Q. The deviation produced by a prism is

NTA AbhyasNTA Abhyas 2020Ray Optics and Optical Instruments

Solution:

Deviation is given by, $\delta=A\left(\mu - 1\right)$
Also, refractive index $\mu \propto \frac{1}{\lambda }$
As $\lambda _{R}>\lambda _{\nu}$
$\therefore \mu _{R} < \mu _{\nu}$
$\therefore \delta_{R} < \delta_{\nu}$