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Q.
The derivative of $f (x) = \sin^2 x$ is
Limits and Derivatives
Solution:
We use the product rule to evaluate this $\frac{df(x)}{dx}$
$= \frac{d}{dx} (\sin \, x \, \sin \,x)$
$=\left(\sin x\right)\sin x+\sin\left(\sin x\right)$
$=\left(\cos x\right)\sin x+\sin\left(\cos x\right)$
$ = 2\, \sin \, x \, cos \, x = \sin \, 2x$