1. Tardigrade
  2. Question
  3. Chemistry
  4. The density of ice at 0°C is 0.915 g/cc and that of liquid water at 0°C is 0.99987 g/cc. The work done for melting 1 mole of ice at 1 .0 0 bar (assuming work is done only due to expansion) is approximately

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Q. The density of ice at $0^{\circ}C$ is $0.915\, g/cc$ and that of liquid water at $0^{\circ}C$ is $0.99987 g/cc$. The work done for melting $1$ mole of ice at $1 .0 0$ bar (assuming work is done only due to expansion) is approximately

Thermodynamics

Solution:

$W=-P\Delta V=10^{5}\frac{N}{m^{2}}\left[\frac{18\times10^{-6}}{0.99987}m^{3}-\frac{18\times10^{-6}}{0.915}m^{3}\right] $
$=+10^{5}\times1.67\times10^{-6}J m=0.167J\sim0.17J $