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  4. The density of a solution prepared by dissolving 120 g of urea (mol. Mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity if this solution is

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Q. The density of a solution prepared by dissolving $120\, g$ of urea (mol. Mass $= 60\, u$) in $1000\, g$ of water is $1.15\, g/mL$. The molarity if this solution is

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Solution:

Total mass of solution $= 1000$ g water $+ 120$ g urea $= 1120\, g$
Density of solution $=1.15\, g/mL$
Thus, volume of solution $ =\frac{\text{mass}}{\text{density}} = \frac{1120\,g}{1.15\,g/mL}$
$= 973.91 \,mL = 0.974 \,L$
Moles of solute $ = \frac{120}{60} = 2\,mol$
Molarity $= \frac{\text{moles of solute}}{\text{volume(L)of solution}}$
$ = \frac{2\, mol}{0.974\,L}$$ = 2.05\, mol \,L^{-1}$