1. Tardigrade
  2. Question
  3. Chemistry
  4. The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity of this solution is :

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Q. The density of a solution prepared by dissolving $120\, g$ of urea (mol. mass = $60\, u$) in $1000 \,g$ of water is $1.15\, g/mL$. The molarity of this solution is :

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Solution:

Molarity $= \frac{mols\, of\, solute}{volume \,of \,sol. \left( \ell\right)}$
$= \frac{120 \times1.15}{60 \times1120} \times1000 = 2.05\,M$