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Q. The density of a liquid is 1.2 g/mL. There are 35 drops in 2 mL. The number of molecules in 1 drop is (molecular weight of liquid = 70)

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Solution:

Volume of one drop $=\frac{2}{35}mL$
Number of moles in one drop $=\frac{2\times1.2}{35\times70}=\frac{1.2}{\left(35\right)^{2}}$
Number of molecules in one drop $=\frac{1.2}{\left(35\right)^{2}}\times N_{A}$
($N_A =$ Avogadro’s number)