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Q. The density of a gas is $ 1.964\text{ }g\text{ }d{{m}^{-3}} $ at 273 K and 76 cm Hg. The gas is

JamiaJamia 2008

Solution:

We know that $ PV=nRT $ Or $ PV=\frac{w}{m}RT $ Or $ m=\frac{m}{V}\frac{RT}{P} $ Or $ M=d\frac{RT}{P} $ $ d=1.964g/d{{m}^{3}}=1.964\times {{10}^{-3}}g/cc. $ $ P=76cm=1atm $ $ R=0.0812\text{ }L\text{ }atm\text{ }{{K}^{-1}}mo{{l}^{-1}} $ $ =82.1\,cc\,atm\,{{K}^{-1}}mo{{l}^{-1}} $ $ T=273K $ $ m=\frac{1.964\times {{10}^{-3}}\times 82.1\times 273}{1}=44 $ The molecular weight of $ C{{O}_{2}} $ is 44. So, the gas is $ C{{O}_{2}} $ .