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Q. The density of $4 M NaOH$ solution is $1.6 g mL ^{-1} .$ The molality of the solution is

Some Basic Concepts of Chemistry

Solution:

$m =\frac{1000 M }{1000 d - MM _{ B }}=\frac{1000 \times 4}{(1000 \times 1.6)-(4 \times 40)}$

$=\frac{4000}{1600-160}=\frac{4000}{1440}$

$=2.77 \,mol \,kg ^{-1}$