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Q. The $\Delta H_{f}^{0}$ for $CO_{2}\left(\right.g\left.\right)$ , $CO\left(\right.g\left.\right)$ and $H_{2}O\left(\right.g\left.\right)$ are $-393.5$ , $-110.5$ and $-241.8kJmol^{- 1}$ respectively. The standard enthalpy changes $\left(\right.inkJ\left.\right)$ for the reaction
$CO_{2}\left(g\right)+H_{2}\left(g\right) \rightarrow CO\left(g\right)+H_{2}O\left(\right.g\left.\right)$ is:

NTA AbhyasNTA Abhyas 2022

Solution:

$\Delta H_{r e a c t i o n}^{^\circ }=\Delta H_{f}^{^\circ }\left(C O\right)+\Delta H_{f}^{^\circ }\left(H_{2} O , g\right)-\Delta H_{f}^{^\circ }\left(C O_{2} , g\right)=-110.5-241.8+393.5=41.2$