1. Tardigrade
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  3. Chemistry
  4. <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/c-5zw7rckiosucmjbw.jpg /> The degree of unsaturation in major product (.B.) will be:

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Q. Question
The degree of unsaturation in major product $\left(\right.B\left.\right)$ will be:

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
In first step bromine is removed by $Ag^{+}$ ion and carbocation is formed which is rearranged in six member ring. In next step, Aldol condensation reaction take place and $\alpha ,\beta $ unsaturated ketone is formed as major product. This product has two pi bonds and two cyclic ring so, it has total of 4 degree of unsaturation.
Degree of unsaturation $=4$ .