1. Tardigrade
  2. Question
  3. Chemistry
  4. The degree of ionisation of HF in 0.100 M aqueous solution is (freezing point of the solution =-0.197° C and Kf for water =186°C)

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Q. The degree of ionisation of $HF$ in $0.100\, M$ aqueous solution is (freezing point of the solution $ =-0.197^{\circ} C $ and $ K_{f} $ for water $ =186^{\circ}C) $

AMUAMU 2013Solutions

Solution:

$\Delta T_{f}=i k_{1} m $
$0.197=i \times 1.86 \times 0.1$
$i=\frac{0.197}{1.86 \times 0.1}=1.059 \approx 1.06$
In case of dissociation, $\alpha=\frac{8-1}{n-1}$
$=\frac{1.06-1}{2-1}=0.06=6 \%$