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Tardigrade
Question
Chemistry
The decreasing order of bond angle is
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Q. The decreasing order of bond angle is
J & K CET
J & K CET 2004
A
$NO _{2}> NO _{2}^{+}> NO _{2}^{-}$
B
$NO _{2}^{-}> NO _{2}> NO _{2}^{+}$
C
$NO _{2}^{+}> NO _{2}> NKO _{2}^{-}$
D
$NO _{2}^{+}> NO _{2}^{-}> NO _{2}$
Solution:
As the number of unpaired electrons (lone pair of electrons) increases, bond angle decreases. Thus, the decreasing order of bond angle is
