1. Tardigrade
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  4. The decomposition of dimethyl ether leads to the formation of CH4,H2 and textCO and the reaction rate is given by rate=k[C H3 O C H3](3/2) The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether i.e. rate=k(PC H3 O C H3)(3/2) , If the pressure is measured in bar and time in minutes, then the unit of rate constants is:

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Q. The decomposition of dimethyl ether leads to the formation of $CH_{4},H_{2}$ and $\text{CO}$ and the reaction rate is given by $rate=k\left[C H_{3} O C H_{3}\right]^{\frac{3}{2}}$

The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether i.e. $rate=k\left(P_{C H_{3} O C H_{3}}\right)^{\frac{3}{2}}$ ,

If the pressure is measured in bar and time in minutes, then the unit of rate constants is:

NTA AbhyasNTA Abhyas 2020Chemical Kinetics

Solution:

As $rate=k\left[C H_{3} O C H_{3}\right]^{\frac{3}{2}}$

bar/min $=k\left(b a r\right)^{\frac{3}{2}}$

Unit of $k=bar^{- \frac{1}{2}} \, m i n^{- 1}$