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Q. The decomposition of a certain mass of $CaCO_3$ gave $11.2 \,dm^3$ of $CO_2$ gas at STP. The mass of $KOH$ required to completely neutralise the gas is

AIIMSAIIMS 2012

Solution:

Weight of $11.2 \,dm ^{3}$ of $CO _{2}$ gas at STP
$=\frac{44}{2}=22\, g$
$\underset{56\,g}{KOH} + \underset{44\,g}{CO _{2} } \longrightarrow KHCO _{3}$
$KOH$ required for complete neutralisation of
$22 \,g \,CO _{2}=\frac{56}{44} \times 22=28\, g$