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Q. The de Broglie wavelength of electron of $He ^{+}$ion is $3.329 \, \mathring{A}$. If the photon emitted upon deexcitation of this $He ^{+}$ion is made to hit $H$-atom in its ground state so as to liberate electron from it, what will be the de-Broglie's wavelength of photoelectron.

Structure of Atom

Solution:

$2.351\, \mathring{A}$