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Q. The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

According to Bohr's theroy
$mvr=\frac{n h}{2 \pi }$
$2\pi r=\frac{n h}{m v}$
$2\pi r=n\lambda $
For n=1, $\lambda =2\pi r$