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  4. The de Broglie wavelength of an electron in the 3rd Bohr orbit is

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Q. The de Broglie wavelength of an electron in the 3rd Bohr orbit is

NTA AbhyasNTA Abhyas 2022

Solution:

We know
$2\pi r=n\lambda $
$n=3$
and $r=a_{0}\frac{n^{2}}{Z}$
$2\pi a_{0}\frac{n^{2}}{Z}=n\lambda $
$2\pi \frac{3^{2} a_{0}}{1}=3\lambda $
$\lambda =6\pi a_{0}$