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Q. The de-Broglie wavelength of an electron having 80 eV of energy is nearly ( $ 1eV=1.6\times {{10}^{-19}}J, $ mass of electron $ =9.1\times {{10}^{-31}}kg, $ Planck's constant $ =6.6\times {{10}^{-34}}kg,s $ )

MGIMS WardhaMGIMS Wardha 2009Dual Nature of Radiation and Matter

Solution:

$ \lambda =\frac{h}{\sqrt{2mE}} $ $ =\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 80\times 1.6\times {{10}^{-19}}}} $ $ =1.4{\AA} $