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  4. The de-Broglie wavelength of an electron accelerated to a potential of 400 V is approximately

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Q. The de-Broglie wavelength of an electron accelerated to a potential of $400 \, V$ is approximately

NTA AbhyasNTA Abhyas 2020

Solution:

Voltage, $V=400 \, V$
$\because \, \, $ the de-Broglie wavelength of an electron
$\lambda =\frac{12.3}{\sqrt{V}}\overset{^\circ }{A}$
$=\frac{12.3}{\sqrt{400}}\overset{^\circ }{A}=\frac{12.3}{20}\overset{^\circ }{A}$
$=0.615 \, \overset{^\circ }{A}$
$ \, \lambda =0.0615 \, nm$