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  4. The de Broglie wavelength of an electron accelerated to a potential of 400 V is approximately

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Q. The de Broglie wavelength of an electron accelerated to a potential of $400\, V$ is approximately

KCETKCET 2016Dual Nature of Radiation and Matter

Solution:

Voltage, $V=400 \,V$
$\because$ de-Broglie wavelength of an electron
$\lambda =\frac{123}{\sqrt{V}} \,\mathring{A}$
$=\frac{12.3}{\sqrt{400}} \,\mathring{A}=\frac{12.3}{20} \,\mathring{A} $
$=0.615 \,\mathring{A}$
$\Rightarrow \lambda =0.0615\, nm$