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  4. The de-Broglie wavelength of a particle is

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Q. The de-Broglie wavelength of a particle is

J & K CETJ & K CET 2012Structure of Atom

Solution:

The de-Broglie wavelength of a particle is inversely proportional to its momentum
$\lambda=\frac{h}{m v} $ (de - Broglie equation)
$\therefore \lambda=\frac{h}{P} $ ($P =$ momentum)